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AFCAT · Numerical Ability

Trains, Boats and Streams

Crack train-crossing and boat-stream sums in under a minute with relative-speed shortcuts and the unit-fraction trick.

11 min read AFCAT level Exam-ready notes By The Cavalier
🎯 What you'll learn
  • Convert km/h to m/s instantly and apply the right train-crossing formula
  • Use relative speed for same-direction and opposite-direction trains
  • Solve upstream, downstream and still-water boat problems with one pair of equations
  • Apply Cavalier shortcuts to finish each sum in well under a minute

Trains, Boats and Streams is one of the most predictable scoring areas in AFCAT Numerical Ability. Almost every paper carries one or two questions, and they all reduce to a single idea: speed equals distance divided by time. Once you lock in relative speed and the upstream-downstream pair, these become 30-second wins. This guide from The Cavalier builds that confidence step by step.

Why this topic is a guaranteed scorer

In AFCAT, every correct answer earns +3 and every wrong one costs −1. With 250+ marks on offer and a tight clock, you cannot afford to lose time on topics that should be automatic. Trains, Boats and Streams is exactly such a topic: the question types repeat year after year, and the maths rarely goes beyond simple arithmetic. A candidate who has drilled these patterns can finish a question in the time another candidate spends merely reading it.

The reason this topic feels intimidating to beginners is the wording, not the mathematics. Phrases like “crosses a platform”, “overtakes”, “rows against the current” sound complicated, but each one simply tells you two things: what distance is covered and which speed to use. Once you train your eye to extract those two pieces, the answer drops out of the master formula every single time.

The whole chapter rests on one master relation. If you internalise it and the two or three derived formulas, you can answer almost any question by inspection rather than by lengthy working.

Key point

Master formula: Speed = Distance ÷ Time, so Distance = Speed × Time and Time = Distance ÷ Speed. Everything in this chapter is a disguised version of this single equation.

Throughout this guide, treat trains and boats as two sides of the same coin. Trains add or subtract speeds because of direction of travel; boats add or subtract because of the current. The arithmetic is identical — only the story changes.

The unit conversion that decides your speed

Train and boat questions mix km/h with metres and seconds. Getting the conversion wrong is the single biggest reason candidates lose marks here, so memorise both directions until they are automatic. Examiners deliberately set the time in seconds and the speed in km/h precisely to catch the unwary.

Key point

To go from km/h to m/s, multiply by 5/18. To go from m/s to km/h, multiply by 18/5.

Why 5/18? Because 1 km = 1000 m and 1 hour = 3600 s, so 1 km/h = 1000/3600 = 5/18 m/s. Keep this as a reflex rather than re-deriving it in the hall. A neat way to remember which fraction goes which way: the bigger unit (km/h) becomes the smaller number (m/s), so you multiply by the smaller fraction, 5/18.

A second reason to be careful is that lengths almost always arrive in metres while many speeds arrive in km/h. The moment you see a train length in metres and a time in seconds, your instinct should be to put the speed into m/s before doing anything else. Train your hand to write the conversion first, so it never gets forgotten halfway through.

Exam tip

Speeds given in m/s and lengths in metres? Keep everything in m/s. Distances in km and time in hours? Stay in km/h. Only convert when the units clash — needless conversion wastes seconds.

What a train actually has to cross

The trick with trains is realising that a train is not a point — it has length. The front of the train reaches the object first, but the train has only finished crossing when its rear clears the object too. The distance it covers while crossing something therefore depends on what that something is.

Key point
  • Crossing a pole, man or point (zero length): distance = length of train.
  • Crossing a platform, bridge or tunnel (has length): distance = length of train + length of object.

So time to cross a pole = (length of train) ÷ speed, while time to cross a platform = (length of train + length of platform) ÷ speed. Always ask one question: does the object have length?

Picture it physically. To pass a thin pole, the train moves forward by exactly its own length — the front passes the pole, then the rest of the carriages follow until the last coach is gone. To pass a 200 m platform, the front must travel the full 200 m of platform plus the train length so that the rear finally steps off the far end. That extra length is the whole game.

Common mistake

Forgetting to add the platform length, or adding it when crossing a pole. A man standing on a platform is still a point — ignore his width.

Relative speed for two trains

When two trains interact, you compare their speeds. The direction decides whether you add or subtract.

Key point
  • Opposite directions (towards or crossing each other): relative speed = sum of speeds.
  • Same direction (one overtaking the other): relative speed = difference of speeds.

Time to cross each other = (sum of both lengths) ÷ relative speed.

Remember

Whether they cross or overtake, the distance covered is always the sum of the two train lengths. Only the relative speed changes with direction.

Why does direction flip the sign? When two trains move towards each other, the gap between them closes at the combined rate, so their speeds add. When one chases the other in the same direction, the faster train only gains on the slower one at the difference of their speeds, so you subtract. This is the heart of every relative-motion question, and it applies to people walking, cars driving and boats rowing just as much as to trains.

A handy result: if two trains of equal length take t1 and t2 seconds to pass a pole, and T seconds to cross each other while moving opposite, the lengths and speeds can all be linked back to the master formula. In the exam, you rarely need that full algebra — just plug numbers into sum-of-lengths over relative-speed and you are done.

Worked example: two trains crossing

Worked example

A 150 m train running at 72 km/h crosses a 250 m train running at 36 km/h in the opposite direction. How long do they take to cross each other?

Relative speed = 72 + 36 = 108 km/h Convert: 108 × 5/18 = 30 m/s Total distance = 150 + 250 = 400 m Time = 400 ÷ 30 = 13.33 s Answer: about 13.3 seconds
Exam tip

Multiples of 18 km/h convert to clean m/s: 18 → 5, 36 → 10, 54 → 15, 72 → 20, 90 → 25. Memorising these saves the 5/18 step entirely.

Boats and streams: the core pair

Now switch to water. A boat has its own speed in still water, but the river current (stream) either helps or fights it.

Key point

Let boat speed in still water = b and stream speed = s.

  • Downstream (with the current): speed = b + s
  • Upstream (against the current): speed = b − s

From these two, the two most useful reverse formulas fall out instantly:

Key point
  • Boat speed in still water = (downstream + upstream) ÷ 2
  • Stream speed = (downstream − upstream) ÷ 2
Remember

Still water is the average of the two speeds; the stream is half the difference. This single line answers a large share of boat questions directly.

It helps to see why these two reverse formulas are true. Add the downstream and upstream speeds: (b + s) + (b − s) = 2b, so dividing by 2 isolates the boat speed b. Subtract them: (b + s) − (b − s) = 2s, so half the difference gives the stream speed s. No memorisation tricks needed — the algebra is two lines long and you can rebuild it any time you blank out.

The same b-and-s pair handles swimmers in a river, an aircraft flying with or against the wind, and a man walking on a moving escalator. The “stream” is just any helping or opposing background speed. Recognising this lets you reuse one method across several disguised question types in the paper.

Worked example: finding boat and stream speed

Worked example

A man rows 30 km downstream in 2 hours and 18 km upstream in 3 hours. Find his speed in still water and the speed of the stream.

Downstream speed = 30 ÷ 2 = 15 km/h Upstream speed = 18 ÷ 3 = 6 km/h Still water = (15 + 6) ÷ 2 = 10.5 km/h Stream = (15 − 6) ÷ 2 = 4.5 km/h Answer: boat 10.5 km/h, stream 4.5 km/h

Notice you never needed to set up algebra. Find the two speeds, then take the average and half-difference.

The round-trip and average-speed traps

A favourite AFCAT trick is the same-distance round trip: a boat goes downstream and returns upstream over the same distance. The average speed for the whole trip is not the simple average of the two speeds. The reason is timing — the boat crawls upstream and so spends far longer at the slow speed than at the fast one, which drags the true average down below the midpoint.

Common mistake

Average speed for a there-and-back journey is the harmonic mean, not (down + up) ÷ 2. Use: average speed = (2 × down × up) ÷ (down + up).

Key point

If a boat covers the same distance up and down, and total time is given, you can also use: distance = (total time × down × up) ÷ (down + up + ... ) only after fixing both speeds. Safest route: find down and up speeds first, then add the two times.

Exam tip

Same logic powers the classic “to-and-fro by train” sum. For equal distances, the to-and-fro average is always the harmonic mean of the two leg speeds — spot it and skip the algebra.

Traps that cost AFCAT candidates marks

  • Unit clash: mixing km/h with metres. Convert before you compute, not after.
  • Forgetting object length: a bridge or tunnel adds to the distance; a pole does not.
  • Wrong sign for stream: downstream adds, upstream subtracts. Re-read the direction.
  • Equal-length assumption: two trains are not always the same length — read carefully.
  • Average-speed slip: round trips use the harmonic mean, never the plain average.
Remember

Underline the units and the direction word the moment you read the question. Ninety percent of errors here are reading errors, not maths errors.

Previous-year style practice

Previous-year style question

Q. A train 120 m long passes a platform 280 m long in 20 seconds. What is the speed of the train in km/h?

Answer: Total distance = 120 + 280 = 400 m. Speed = 400 ÷ 20 = 20 m/s. Convert: 20 × 18/5 = 72 km/h. So the train moves at 72 km/h.

This is the exact shape of most AFCAT train questions: a length, a platform, a time, and one conversion at the end. Notice the discipline — add the two lengths first, divide by time to get m/s, and only then convert to km/h because the options were in km/h. Reverse the order and you will still arrive at the same answer, but doing it in this sequence keeps your units clean and your mind calm under the clock.

Boat questions follow an equally fixed template: a downstream time, an upstream time, and a request for either the boat speed, the stream speed, or a total journey time. Spot which of the three is being asked, reach for the matching one-line formula, and you will almost never need to write a system of equations.

Cavalier speed strategy in the exam hall

To turn knowledge into marks under time pressure, follow a fixed routine for every question:

  1. Read the direction words (towards, same, downstream, upstream) and circle them.
  2. Decide: do I add or subtract speeds?
  3. Decide: does the object have length to add to the distance?
  4. Match units — convert once if needed.
  5. Apply the master formula and pick the option.
Exam tip

If a question demands heavy algebra, flag it and move on. With negative marking, a clean +3 elsewhere is worth more than a risky guess here.

Quick revision

60-second recap
  • Speed = Distance ÷ Time governs the entire chapter.
  • km/h to m/s: × 5/18; m/s to km/h: × 18/5.
  • Pole → train length only; platform/bridge → train + object length.
  • Opposite trains: add speeds; same direction: subtract.
  • Downstream = b + s; upstream = b − s; still water = average; stream = half difference.
  • Round trips use the harmonic mean, never the plain average.

Frequently asked questions

How many questions on Trains, Boats and Streams come in AFCAT?

Typically one or two questions appear in the Numerical Ability section. Because the formulas repeat, it is among the safest and fastest topics to secure full marks on.

What is the fastest way to convert km/h to m/s?

Multiply by 5/18. For clean multiples of 18 km/h, memorise 36 = 10 m/s, 54 = 15, 72 = 20, 90 = 25 m/s to skip the calculation entirely.

When do I add the platform length to the distance?

Add it whenever the train crosses something that has length: a platform, bridge or tunnel. For a pole, signal post, man or point, the distance is just the train's own length.

How do I find boat speed and stream speed quickly?

Boat speed in still water is the average of downstream and upstream speeds, and stream speed is half their difference. Find the two travel speeds first, then apply these two one-line formulas.

Why is round-trip average speed not the simple average?

Because the boat spends more time at the slower upstream speed, the correct average for equal distances is the harmonic mean: (2 x down x up) divided by (down + up).

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